Date: Sun, 27 Feb 2000 04:29:49 GMT From: wwwnopsamus-technologies.com (Dean Malandris) Subject: Dimensions of SAAB Tool #8791618 for Clutch Replacement on late model 900s
OK I found the hand drawing I made when I borrowed one of these from a local wrecker's garage late last year so I could get the defective slave cylinder out of my 1990 900T. I don't have my scanner back up and running yet, so a description of the dimensions, and reliance on you having access to a Bentley manual so you know what a picture of the tool looks like will have to suffice. It's very straightforward though. The tool is made from a strip of spring steel, rectangular cross-section of 2,0 mm x 4,0 mm. 1) Cut a strip of approximate length 520 mm (this is a little longer than we really need, but you can trim the end off when you're done). 2) Bend the steel to form a perfectly round (well, as closely as you can, anyway) ring with I.D. of 158,0 mm. If you placed the ring down onto a sheet of paper, then looking down onto the plane, you would see a section thickness of 2,0 mm. In other words, the 4,0 mm section would be the wall height if you viewed the ring side-on, parallel to the plane of the page. This 4,0 mm wall is what actually pushes down on the fingers in the pressure plate, so it's important to bend the steel along the right axis! 3) Now, using an actual sheet of A4 paper and a compass, draw a circle of diameter 158,0 mm and mark the centre. Call the point at the centre of the circle (o). Draw a radial line from (o) to any point on the circumference. Where the radial line intersects the circumference, we'll call (a). Now draw another radial line from (o) to another point on the circumference, where the point of intersection is 40,0 mm of arc length away from (a) and in a clockwise direction with respect to it. Mark this point of intersection (b). So what we have so far, is two points (a) and (b) on the circumference of a circle 158,0 mm diameter, with (b) being 40,0 mm of arc length away from (a), and (b) is located clockwise of (a). 4) On the radial line (ob), draw a short arc of radius 61,0 mm. Call the point of intersection (x). In other words, (x) lies on (ob) at a distance of 61,0 mm from the centre (18,0 mm inwards from the diameter of the circle). 5) Place the ring onto the circle you have drawn, and align the end of the ring that finishes in a clockwise direction at (a). By that I mean if you imagine an arrow head or a vector coming "out" of the tip of the steel, it points in a clockwise direction. 6) Grabbing the other (free) end of the steel, bend it so the outside edge of the 2,0 mm section aligns with the radial line (ob). So what you will have is: a ring that starts at (a), goes in an anti-clockwise direction until you are about 40mm away from completing the circle, then you make a sharp left turn so that the outside edge of the 2,0 mm wall aligns with (ob), thus forming a ring with a 40mm gap in it and an "L" shaped bit left over, pointing to the centre of the circle, in the plane of the page. 7) Now where the length of steel runs along (ob), locate (x). At this point, the steel rises up vertically out of the plane of the paper. Bend the steel upwards (this is a little tougher as now you're bending the the 4,0 mm section along its axis, whereas before, you were bending the 2,0 mm section along its axis) and trim so that the end of the steel is 24,0 mm high above the plane of the paper. This forms the handle. The handle is sort of like an S-shape, with one leg of the S in the plane, and one leg normal to the plane. That's it. It really is simpler to make than it sounds, and I hope the details are easy enough to follow, even if you don't know what the tool actually looks like. -- Alcohol and calculus don't mix. Never drink and derive. ---------------------------------------------------------------------------- Plexus Technologies Pty. Limited. Electronics Consulting, Research & Development. http://www.plexus-technologies.com Mobile: +61 (0)411 470 880 ICQ: 719010
