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Re: what's the actual rolling size difference? Posted by JimBlake [Email] [Profile/Gallery]
(more from JimBlake) on Sun, 15 Sep 2013 19:23:40
In Reply to: 5% size difference?, Bill Homer [Profile/Gallery]
, Sat, 14 Sep 2013 12:54:57
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If you get the same size tires, the difference in wear is a lot less than 5%. I don't know what tire size, but say 25.5-inch overall tread diameter.
Tread is usually 10/32 when it's new, 2/32 is down to the wear bars. So 8/32 is the difference between new & all-worn-out. That 8/32 becomes 16/32 when you talk about the full diameter of the tire. That's less than 2% and really even less than that because the 2 tires you want to save aren't COMPLETELY worn out.
Now I'd be interested in a tire engineer to comment on this next idea...
A tire doesn't act like a perfectly rigid disk, but that's how everyone is describing it. It deforms where it rolls against the ground. I suspect that the tread-belt is the REAL controlling structure that determines the revolutions-per-mile. The tread structure seems too compliant to control things completely.
, Sat, 14 Sep 2013 12:54:57
, Sun, 15 Sep 2013 21:13:52
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